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2.3x^2-9x-18=0
a = 2.3; b = -9; c = -18;
Δ = b2-4ac
Δ = -92-4·2.3·(-18)
Δ = 246.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{246.6}}{2*2.3}=\frac{9-\sqrt{246.6}}{4.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{246.6}}{2*2.3}=\frac{9+\sqrt{246.6}}{4.6} $
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